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sebbmeistOr

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741

Thursday, March 31st 2011, 9:23pm

ax² + ax/2 - 1 = 0 = 2ax² + ax -2

x1,2 = (-a +- wurzel ( a² + 16a) ) /4

also x1 und x2 unterscheiden sich im vorzeichen vor der wurzel ...

setzt ich nun beide gleich ... und form um ... a²+ 16a =0 ... a1 = 0, a2 = -16 ...

für a1 = 0 passt aber die grundgleichung nichmehr ... 0 ist net gleich -1 ...

d.h. a2 = -16 sollte die lösung sein :)
kann man auch kontrollieren.
wenn man nun die -16 anstelle von a in das binomwurzelteil einsetzt, wird die wurzel zu 0, also steht da +- 0 ... man bekommt also nur ein ergebnis.

q.e.d. :D



gruß seb

This post has been edited 1 times, last edit by "sebbmeistOr" (Apr 1st 2011, 12:23pm)


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742

Friday, April 1st 2011, 9:58am



ax² + ax/2 - 1 = 0 = 2ax² + ax -1



Hab mir den Rest gar nicht mehr durchgelesen, aber wenn du den Term mal 2 nimmst müsste -2 dastehen - kannst den Faktor ja nicht durch das a korrigieren, oder steh ich grad aufm Schlauch? Naja muss weg..

sebbmeistOr

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743

Friday, April 1st 2011, 12:22pm

jo hast recht :)
ändert aber nichts am vorgehen.
habs ma editiert...



gruß seb

FunGun

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744

Saturday, April 2nd 2011, 7:55pm

x²+x/2-1/a=0
x1,2=-1/4+-Wurzel(1/16+2/a)

Gleiche Idee wie Sebb, also Wurzel(1/16-1/a)=0
Quadrieren: 1/16-1/a=0
-1/a: 1/16=1/a
Kehrwert: 16=a

finde ich etwas übersichtlicher als das andere...

Blaight

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745

Sunday, April 3rd 2011, 3:22pm

Kann mir einer erklären, was Epigenetik ist?
Mit den besten Grüßen,
Blaight

Marley

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746

Sunday, April 3rd 2011, 3:49pm

Dazu gibt es wirklich genug Arikel im Internet.... studiere selbst Biologie und denke dass der ein oder andere Artikel auch so verständlich ist!


Epigenetik - Lexikon - biosicherheit.de
Was ist Epigenetik? Was verbirgt sich unter diesem Oberbegriff? | COSMiQ

Blaight

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747

Monday, April 4th 2011, 12:23am

Danke Dir, studierst Du auf Master?
Mit den besten Grüßen,
Blaight

Marley

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748

Monday, April 4th 2011, 9:42am

Bin noch im Bachelor...fürs Master müsst ich jetzt vorallem notentechnisch noch was drauflegen! Aber machen will ich den Master aufjedenfall...ohne ist man ziemlich aufgeschmissen!

Blaight

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749

Monday, April 4th 2011, 10:56am

Welche Schwerpunkte interessieren Dich? Molekkularbiologisch, oder ökologisch oder so?
Mit den besten Grüßen,
Blaight

Marley

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750

Monday, April 4th 2011, 1:35pm

Mit Botanik/zoologie/ökologie kann man in der Regel nichts holen daher ist das nur was für Optimisten. Aber die Fächer sind im Grundstudium ganz cool....zeichnen etc... ist mal was anderes zum chemischen Rest!
Ich werd aber sicher im Bereich mol.Zellbiologie/biochemie/Genetik weiter machen.


Jetzt hab ich aber noch was für den Thread:

Ein ball wird 10m hoch in die Luft geworfen. Es dauert 2,85s bis er am Boden ankommt. Wie lang dauert es wenn der Ball 20m hoch geworfen wird.? (reibung vernachlässigen)

Das ist eine Multiplechoicefrage.... ich komm auch irgendwie auf die Lösung aber nur durch probieren/einsetzen der Antwortmöglichkeiten aber wie komm ich direkt auf die Lösung.?

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751

Monday, April 4th 2011, 1:45pm

Was ist denn die Antwort? ~4 sec?

Nyytii

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752

Monday, April 4th 2011, 3:25pm

also da ja bei dem wurf nach oben die gesamte Kinetische Energie in Potentielle umgewandelt wird kannst die Kinetische und die Potentielle gleichsetzen:

mgh = 1/2 mv² --> m kürzt sich hinaus , nach v auflösen , dann hast du die geschwindigkeit die der ball bei loswerfen hatte
2*g*h = v² --> Ergebniss ist die geschwindigkeit die der ball beim loswerfen hatte , also ergebnis durch 2 teilen und du erhältst die Durchschnittsgesch.
ungefähr 7 m/s (bei 10 wurfhöhe) , also da der ball insgesamt 20 meter zurücklegt (Nach oben und nach unten fliegen) teilst du 7/20 = 2,86 s

Und genau dasselbe nur mit den anderen werten einfach für den vorgang bei 20 metern Machen ;)
Überzeugter Pastafari , lasst euch von seinen Nudligen Anhängseln Berühren !
Positiv gehandelt mit : Sandberg (2x) , Smokyroyal , frozz , lil shishaaa , ImbissMau
"Das ist eine sehr objektive Frage, die Dir jeder anders beantworten wird." (ToniM 7.2.2012)

Marley

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753

Monday, April 4th 2011, 4:48pm

ja 4 Sekunden ist richtig....

danke!

sebbmeistOr

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754

Monday, April 4th 2011, 5:13pm

najo man könnte es auch penibel ausrechnen ^^ ...

beim hochwerfen hat man die höhe h , die negative beschleuniging g ...

(energieansatz...)
m*g*h = 1/2 *m * v0^2 ... -> v0 (abwurfgeschw.)

(s=s0+vo*t + a/2 t^2 ...)
h= v0*t - g/2 *t^2 ... -> t hochwerf ...

und rückwärts ...

h = g/2 * t^2 -> t runter ...



gruß seb

Nightwish

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755

Wednesday, April 6th 2011, 9:16pm

Schreibe bald ne Logik Klausur. Hier mal ne scheinbar leichte Aufgabe zum vereinfachen, komme einfach nicht aufs richtige Eregbnis:

( nicht(p) v nicht(q) v p ) ^ ( (p ^ q) v nicht(p) )

Das Ergebnis sollte sein: nicht(p) v q

ich komme allerdings jedesmal auf nicht(q) ^ nicht(p)

kann das mal wer schritt für schritt aufzeigen vielleicht? ;-)

Blubberbär

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756

Wednesday, April 6th 2011, 9:39pm

Damit komme ich auf dein richtiges Ergebnis. Ich muss allerdings zugeben, dass ich da selber auch nicht drauf gekommen bin. Hatte einmal dein falsches Ergebnis und noch eine dritte Variante 8)

Gruß

Nightwish

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757

Wednesday, April 6th 2011, 10:07pm

hmm danke für den Link, leider kann ich die Zwischenschritte dort nicht nachvollziehen...

Edit: Habe meinen Fehler gefunden, mein Vorgehen:

( nicht(p) v nicht(q) v p ) ^ ( (p ^ q) v nicht(p) ) | In der ersten Klammer ergibt nicht(p) v p = 1, das ganze mit und/oder nicht(q) ergibt ja weiterhin 1 (da lag schon mein Fehler)

= (nicht(p) v p ) ^ (nicht(p) v q) | da ja nicht(p) v p = 1 ist, ist die Schnittmenge hier nicht(p) v q

= nicht(p) v q


So müsste es alles passen denke ich

This post has been edited 1 times, last edit by "Nightwish" (Apr 6th 2011, 10:51pm)


iBot

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758

Wednesday, April 6th 2011, 10:44pm

"Die booleschen Operatoren werden angegeben als AND: *, OR: +, NOT: ~."

Wäre hilfreich wenn du die auch mal definierst^^

Rus

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759

Thursday, April 7th 2011, 3:06pm

Muss die Extremstellen einer Funktion ausrechnen:
f(x)= wurzel von x -x
Wäre dankbar wenn mir jemand helfen könnte^^

Quoted

Original von DennisD
Kumpels is im Park mal der Tabak ausgegangen, also haben die ne Raupe geraucht,

:lol: :lol: :lol: :lol:

FunGun

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760

Thursday, April 7th 2011, 3:15pm

Extremstellen sind Nullstellen in der ersten Ableitung. Also erste Ableitung bilden und gleich null setzen. Dabei dann noch beachten, dass Wurzel(x) = x^(1/2) ist und dann dürfte es kein Problem sein.

[edit] ^ und v als boolsche Operatoren lernt man im Informatikstudium.